The sum of three consecutive integers is 258. How do you find the three integers?

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Answer 1 · 2016-11-04T22:07:33

$The consecutive integers are 85,86,87$ $"The consecutive integers are 85,86,87"$

$n : the first number$ $n:"the first number"$

$n + 1 : the second number$ $n+1:"the second number"$

$n + 2 : the third number$ $n+2:"the third number"$

$n + (n + 1) + (n + 2) = 258$ $n+(n+1)+(n+2)=258$

$3 n + 3 = 258$ $3n+3=258$

$3 n = 258 - 3$ $3n=258-3$

$3 n = 255$ $3n=255$

$n = \frac{255}{3}$ $n=255/3$

$n = 85$ $n=85$

$n + 1 = 85 + 1 = 86$ $n+1=85+1=86$

$n + 2 = 85 + 2 = 87$ $n+2=85+2=87$