The sum of three consecutive integers is 267. What are the three integers?

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Answer 1 · 2016-07-12T11:53:45

The digits are $88, 89, 90$ $88, 89, 90$

Let the starting digit be $x$ $x$

Then the other two digits are -

$x + 1$ $x+1$
$x + 2$ $x+2$

Form an equation

$x + (x + 1) + (x + 2) = 267$ $x+(x+1)+(x+2)=267$

Solve it

$x + x + 1 x + 2 = 267$ $x+x+1x+2=267$

$3 x + 3 = 267$ $3x+3=267$
$3 x = 267 - 3 = 264$ $3x=267-3=264$
$x = \frac{264}{3} = 88$ $x=264/3=88$

The first digit is $88$ $88$
The second digit is $89$ $89$
The third digit is $90$ $90$