The sum of three consecutive odd numbers is 159. What is the smallest of the three numbers?

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The sum of three consecutive odd numbers is 159. What is the smallest of the three numbers?

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Answer 1 · 2016-11-01T00:08:10

$51$ $51$

Explanation:

Let $n$ $n$ represent the least of the odd numbers. Then the next two will be $n + 2$ $n+2$ and $n + 4$ $n+4$ . That their sum is $159$ $159$ gives us

$n + (n + 2) + (n + 4) = 159$ $n+(n+2)+(n+4) = 159$

$\Rightarrow 3 n + 6 = 159$ $=> 3n+6 = 159$

$\Rightarrow 3 n = 153$ $=> 3n = 153$

$:. n = 51$

Checking, we find that $51+53+55 = 159$ as desired.

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The sum of three consecutive odd numbers is 159. What is the smallest of the three numbers?

1 Answer

Explanation:

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