The sum of two consecutive even integers is 50. What are the numbers?

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Answer 1 · 2016-07-14T14:17:08

First even $=24$
Second even $=26$

let $2x$ be the first even integer
let $2x+2$ be the second even integer

$2x+(2x+2)=50$

$4x=48$

$x=12$

First even integer

$2x=2(12)=24$

Second even integer

$2x+2=2(12)+2=26$

God bless....I hope the explanation is useful.

Answer 2 · 2016-07-14T14:20:09

$24, 26$

Note that even integers occur after every odd integer ( $color(blue)(6)$ , 7, $color(blue)(8)$ ). Let's write an equation.

One integer can be $n$ . The other one must be $n + 2$ since an even integer occurs every two numbers.

$n + (n+2) = 50$

This is our equation. We need to solve for $n$ .

$2n + 2 = 50$

$2n = 48$

$n = 24$

We found that $n$ is $24$ . This means that the other even integer, $n+2$ , is $26$ . We can go ahead and add these values to see if it equals $50$ .

$24 + 26 = 50$

It does equal $50$ , so our numbers are correct.