The temperature T at a distance, d meters from a heat source is inversely proportional to the square of the distance. When d=4 t=275 how do you find t when d=6?

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The temperature T at a distance, d meters from a heat source is inversely proportional to the square of the distance. When d=4 t=275 how do you find t when d=6?

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Answer 1 · 2018-02-23T11:57:10

$T = 122 . ¯ 2$ $T=122.bar(2)$

Explanation:

$the initial statement is T \propto \frac{1}{d^{2}}$ $"the initial statement is "Tprop1/d^2$

$to convert to an equation multiply by k the constant$ $"to convert to an equation multiply by k the constant"$
$of variation$ $"of variation"$

$\Rightarrow T = k \times \frac{1}{d^{2}} = \frac{k}{d^{2}}$ $rArrT=kxx1/d^2=k/d^2$

$to find k use the given condition$ $"to find k use the given condition"$

$when d = 4, T = 275$ $"when "d=4,T=275$

$T = \frac{k}{d^{2}} \Rightarrow k = T \times d^{2} = 275 \times 16 = 4400$ $T=k/d^2rArrk=Txxd^2=275xx16=4400$

$"equation is " color(red)(bar(ul(|color(white)(2/2)color(black)(T=4400/d^2)color(white)(2/2)|)))$

$"when "d=6" then"$

$T=4400/36=122.bar(2)$

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The temperature T at a distance, d meters from a heat source is inversely proportional to the square of the distance. When d=4 t=275 how do you find t when d=6?

1 Answer

Explanation:

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