The Tigers won twice as many football games as they lost. They played 96 games. How many games did the win?

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Answer 1 · 2016-12-07T14:09:51

They Tigers won 64 games.

Let's call the games the Tigers won $w$ $w$ and the games they lost $l$ $l$ .

With the information provided in the question we can write two equations we can solve using substitution:

Because we know they played 96 games we know we can add the wins and losses to equal 96:

$w + l = 96$ $w + l = 96$

And, because we know they won twice as many games as they lost we can write:

$w = 2 l$ $w = 2l$

Because the second equation is already in terms of $w$ $w$ we can substitute $2 l$ $2l$ for $w$ $w$ in the first equation and solve for $l$ $l$ :

$2 l + l = 96$ $2l + l = 96$

$3 l = 96$ $3l = 96$

$\frac{3 l}{3} = \frac{96}{3}$ $(3l)/3 = 96/3$

$l = 32$ $l = 32$

We can now substitute $32$ $32$ for $l$ $l$ in the first equation and calculate $w$ $w$ .

$w = 2 \times 32$ $w = 2 xx 32$

$w = 64$ $w = 64$