The volume of gas in a balloon is 1.90 L at 21.0°C. The balloon is heated, causing it to expand to a volume of 5.70 L. What is the new temperature of the gas inside the balloon?

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Answer 1 · 2017-09-05T03:59:39

We use old Charles' law.....and get #T_2=879.6*K#....

#V_1/T_1=V_2/T_2#; this assumes a given quantity of gas, and absolute temperatures......

And so....#T_2=V_2/V_1xxT_1=(5.70*L)/(1.90*L)xx(21.0+273.13*K)#

#=??*K#