The width of a rectangle is 3 less than twice the length x. If the area of the rectangle is 43 square feet, what equation can be used to find the length, in feet?

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Answer 1 · 2016-10-20T00:43:26

Use the quadratic formula

$w = 2 x - 3 and l = x$ $w = 2x-3 " " and " " l = x$

$Length x Width = Area$ $"Length x Width = Area"$ .

$x \times (2 x - 3) = 43$ $x xx(2x -3 ) = 43$

Using the distributive property to multiply across the parenthesis gives

$2 x^{2} - 3 x = 43$ $2x^2 - 3x = 43" "$ Subtracting 43 from both sides gives.

$2 x^{2} - 3 x - 43 = 0$ $2x^2 -3x -43 = 0$

This trinomial can not be easily factored so it is necessary to use the quadratic formula.