Triangle A has an area of #18 # and two sides of lengths #8 # and #8 #. Triangle B is similar to triangle A and has a side of length #8 #. What are the maximum and minimum possible areas of triangle B?

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Answer 1 · 2017-12-21T14:03:51

Area of triangle B = 18 as the two triangles are congruent.

#Delta s A and B # are similar.

Since triangle A is isosceles, triangle B will also be isosceles.

Also sides of triangles A & B are equal (both are 8 in length), both the triangles are identical.

Hence area of triangle A = Area of triangle B = 18