Two charges of # 1 C # and # -2 C # are at points # (0,4,2) # and # ( 5,3,7)#, respectively. Assuming that both coordinates are in meters, what is the force between the two points?

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Answer 1 · 2017-04-17T13:27:22

#F=-3.5*10^8" Newtons"#

#"First,you should find the distance between two point given."#

#r^2=(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2#

#P_1(x_1,y_1,z_1)=(0,4,2)#
#P_2(x_2,y_2,z_2)=(5,3,7)#

#r^2=(5-0)^2+(3-4)^2+(7-2)^2#
#r^2=25+1+25#
#r^2=51#

#"Now ,we can use the Coulomb's law to calculate force between two charge."#

#F=K*(Q_1*Q_2)/r^2#

#"Where "Q_1=1C" , "Q_2=-2C" , "r^2=51" , "K=9*19^9#

#F=(9.10^9*1*(-2))/51#

#F=-0.35*10^9" Newtons"#

#"The minus sign means that there is an attractive force between two charges."#