Question

Two charges of `-1 C` and `-2 C` are positioned on a line at points `-6` and `4`, respectively. What is the net force on a charge of `3 C` at `1`?

Answer 1

`vec F_R=-5.45*10^9" "N" attractive force"`

Explanation:

`"data given:"`

`k=9.10^9 N*m^2*C^-2`

`F=k*(Q_1*Q_2)/r^2" Coulomb's law"`

`Q_1=-1C`

`Q_2=-2C`

`Q_3=3C`

`"solution:"`

`vec F_1=k(Q_1*Q_3)/r^2" ; "vec F_1=k((-1)*3)/7^2" ; "vec F_1=-(3k)/49`

`vec F_2=k(Q_2*Q_3)/R^2" ; "vec F_2=k((-2)*3)/3^2" ; "vec F_2=(-6k)/9`

`vec F_2 > vec F_1`

`vec F_R=vec F_2- vec F_1`

`vec F_R=-(6k)/9+(3k)/49`

`vec F_R= (-294k+27k)/441`

`vec F_R=(-267k)/441" ; "vec F_R=-(267*9*10^9)/441`

`vec F_R=-5.45*10^9" "N" attractive force"`