Two charges of 1C and 5C are at points (1,0,3) and (3,5,81), respectively. Assuming that both coordinates are in meters, what is the force between the two points?

1 Answer
Jan 5, 2018

The force is =6.3106N

Explanation:

The force between 2 charges q1 and q2 is

F=kq1q2r2

Where r is the distance between the charges.

And the constant k=9109Nm2C2

The charge q1=1C

The charge q2=5C

The distance is

r=(31)2+(50)2+(813)2=16+25+7056

=7097

Therefore,

The force is =9109(1)(5)7097=0.0063109=6.3106N

The negative sign indicates that the force is attractive