Two corners of a triangle have angles of # (2 pi )/ 3 # and # ( pi ) / 6 #. If one side of the triangle has a length of # 13 #, what is the longest possible perimeter of the triangle?

1 Answer
Oct 16, 2017

Longest possible perimeter = 48.5167

Explanation:

#a/sin a = b/sin b = c/sin c#
The three angles are #(2pi)/3, pi/6, pi/6#

To get the longest possible perimeter, given side should correspond to the smallest angle #pi/6#

#13/sin (pi/6) = b/sin (pi/6) = c/sin ((2pi)/6)#
#b=13, c = (13 * (sin ((2pi)/3)/sin (pi/6))#
#c = (13 * sin120)/sin 60 = (13 * (sqrt3/2))/(1/2)#
#sin (pi/6) = 1/2, sin ((2pi)/3) = sin (pi/3) = sqrt3 / 2#
#c = 13*sqrt3=22.5167#

Perimeter # = 13+13+22.5167=48.5167#