Two corners of a triangle have angles of 3π4 and π12. If one side of the triangle has a length of 7, what is the longest possible perimeter of the triangle?

1 Answer
May 20, 2018

Longest possible perimeter of the triangle is

=39.64 units

Explanation:

ˆA=3π4,ˆB=π12,ˆC=π3π4π12=π6

To get the longest perimeter, side of length 7 should correspond to the least angle π12

Applying Law of Sines,

asinA=bsinB=csinC

asin(3π4)=7sin(π12)=csin(π6)

a=7sin(3π4)sin(π12)=19.12

c=7sin(π6)sin(π12)=13.52

Perimeter =a+b+c=19.12+7+13.52=39.64