Two corners of a triangle have angles of 5π12 and 3π8. If one side of the triangle has a length of 15, what is the longest possible perimeter of the triangle?

1 Answer
Jun 25, 2017

The longest perimeter is =61.6

Explanation:

The third angle of the triangle is

=π(512π+38π)

=π(1024π+924π)

=π1924π=524π

The angles of the triangle in ascending order is

512π>924π>524π

To get longest perimeter, we place the side of length 15 in font of the smallest angle, i.e. 524π

We apply the sine rule

Asin(512π)=Bsin(38π)=15sin(524π)=24.64

A=24.64sin(512π)=23.8

B=24.64sin(38π)=22.8

The perimeter is

P=15+23.8+22.8=61.6