Two corners of a triangle have angles of 5π8 and π12. If one side of the triangle has a length of 1, what is the longest possible perimeter of the triangle?

1 Answer
Nov 23, 2016

The longest possible perimeter is P10.5

Explanation:

Let A=π12
Let B=5π8
Then C=π5π8π12
C=7π24

The longest perimeter occurs, when the given side is opposite the smallest angle:

Let side a=the side opposite angle A=1

The perimeter is: P=a+b+c

Use the Law of Sines

asin(A)=bsin(B)=csin(C)

to substitute into the perimeter equation:

P=a1+sin(B)+sin(C)sin(A)

P=11+sin(5π8)+sin(7π24)sin(π12)

P10.5