Two corners of a triangle have angles of $\frac{5 π}{8}$ $(5 pi )/ 8$ and $\frac{π}{2}$ $( pi ) / 2$ . If one side of the triangle has a length of $7$ $7$ , what is the longest possible perimeter of the triangle?

Question

1145 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-05T13:41:35

Sum needs correction

Sum of the angles of a triangle $= π$ $=pi$

Two angles are $\frac{5 π}{8}, \frac{π}{2}$ $(5pi)/8, pi/2$
As the sum of two angles are greater than $π$ $pi$ sum needs correction.

Two corners of a triangle have angles of 5π8 (5 pi )/ 8 and π2 ( pi ) / 2 . If one side of the triangle has a length of 7 7 , what is the longest possible perimeter of the triangle?