Two corners of a triangle have angles of (5 pi )/ 8 5π8 and ( pi ) / 3 π3. If one side of the triangle has a length of 14 14, what is the longest possible perimeter of the triangle?

1 Answer
Apr 15, 2016

=206=206

Explanation:

Let in DeltaABC,/_A=pi/3,/_B=5pi/8
and /_C =(pi-pi/3-5pi/8)=pi/24
So smallest angle /_C=pi/24
For having a triangle of largest perimeter , let the side of given length be the smallest side c=14
a/sinA=c/sinC
:.a= (csinA)/sinC=14xxsin(pi/3)/sin(pi/24)~~92.9

b= (csinB)/sinC=14xxsin(5pi/8)/sin(pi/24)~~99.1

So the largest possible perimeter
a+b+c=92.9+99.1+14 =206