Two corners of a triangle have angles of π8 and π3. If one side of the triangle has a length of 2, what is the longest possible perimeter of the triangle?

1 Answer
Apr 6, 2016

The maximum perimeter is: 11.708 to 3 decimal places

Explanation:

When ever possible draw a diagram. It helps to clarify what you are dealing with.

Tony B

Notice that I have labeled the vertices as with capital letters and the sides with small letter version of that for the opposite angle.

If we set the value of 2 to the smallest length then the sum of sides will be the maximum.

Using the Sine Rule

asin(A)=bsin(B)=csin(C)

asin(π8)=bsin(1324π)=csin(π3)

Ranking these with the smallest sine value on the left

asin(π8)=csin(π3)=bsin(1324π)

So side a is the shortest.

Set a=2

c=2sin(π3)sin(π8) = 4.526 to 3 decimal places

b=2sin(1324π)sin(π8)=5.182 to 3 decimal places

So the maximum perimeter is: 11.708 to 3 decimal places