Two corners of an isosceles triangle are at (1,3) and (9,7). If the triangle's area is 64, what are the lengths of the triangle's sides?

1 Answer
Dec 10, 2016

The sides of the triangle are a=c=15andb=80

Explanation:

Let the length of side b equal the distance between the two given points:

b=(91)2+(73)2

b=(8)2+(4)2

b=80

Area=12bh

2Area=bh

h=2Areab

h=2(64)80

h=12880

If side b is NOT one of the equal sides then the height is one of the legs of a right triangle and half of the length side b, 802 is the other leg. Therefore, we can use the Pythagorean Theorem to find the length of hypotenuse and this will be one of the equal sides:

c= (12880)2+(802)2

c15

We need to find whether a triangle with sides, a=c=15andb=80 has an area of 64.

I used a Heron's Formula Calculator and discovered that the area is 64.

The sides of the triangle are a=c=15andb=80