Two corners of an isosceles triangle are at $(1, 7)$ $(1 ,7 )$ and $(2, 3)$ $(2 ,3 )$ . If the triangle's area is $6$ $6$ , what are the lengths of the triangle's sides?

Question

1317 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-05T13:16:51

Measure of the three sides are (4.1231, 3.5666, 3.5666)

enter image source here
Length $a = \sqrt{{(2 - 1)}^{2} + {(3 - 7)}^{2}} = \sqrt{17} = 4.1231$ $a = sqrt((2-1)^2 + (3-7)^2) = sqrt 17 = 4.1231$

Area of $Delta = 6$
$:. h = (Area) / (a/2) = 6 / (4.1231/2) = 6 / 2.0616 = 2.9104$

$side b = sqrt((a/2)^2 + h^2) = sqrt((2.0616)^2 + (2.9104)^2)$
$b = 3.5666$

Since the triangle is isosceles, third side is also $= b = 3.5666$

Two corners of an isosceles triangle are at (1 ,7 )(1,7)(1 ,7 ) and (2 ,3 )(2,3)(2 ,3 ). If the triangle's area is 6 66 , what are the lengths of the triangle's sides?