Two corners of an isosceles triangle are at $(2, 5)$ $(2 ,5 )$ and $(4, 8)$ $(4 ,8 )$ . If the triangle's area is $6$ $6$ , what are the lengths of the triangle's sides?

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Two corners of an isosceles triangle are at $(2, 5)$ $(2 ,5 )$ and $(4, 8)$ $(4 ,8 )$ . If the triangle's area is $6$ $6$ , what are the lengths of the triangle's sides?

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Answer 1 · 2018-05-12T04:49:09

$lengths of sides of the triangle are 3.61, 3.77, 3.77$ $color(green)("lengths of sides of the triangle are " 3.61, 3.77, 3.77$

Explanation:

![https://byjus.com/isosceles-triangle-formula]( useruploads.socratic.org )

$A (2, 5), C (4, 8), Area of triangle A_{t} = 6$ $A (2,5), C (4,8), " Area of triangle "A_t = 6$

$¯ ¯¯¯¯ ¯ A C = b = \sqrt{{(4 - 2)}^{2} + {(8 - 5)}^{2}} = \sqrt{13} = 3.61$ $bar (AC) = b = sqrt((4-2)^2 + (8-5)^2) = sqrt13 = 3.61$

$h = \frac{2 \cdot A_{t}}{b} = \frac{2 \cdot 6}{3.61} = 3.32$ $h = (2 * A_t) / b = (2 * 6) / 3.61 = 3.32$

$a = \sqrt{h^{2} + {(\frac{b}{2})}^{2}} = \sqrt{{3.32}^{2} + {(\frac{3.61}{2})}^{2}} = 3.77$ $a = sqrt(h^2 + (b/2)^2) = sqrt(3.32^2 +( 3.61/2)^2) = 3.77$

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Two corners of an isosceles triangle are at $(2, 5)$ $(2 ,5 )$ and $(4, 8)$ $(4 ,8 )$ . If the triangle's area is $6$ $6$ , what are the lengths of the triangle's sides?

1 Answer

Explanation:

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Two corners of an isosceles triangle are at (2 ,5 )(2,5)(2 ,5 ) and (4 ,8 )(4,8)(4 ,8 ). If the triangle's area is 6 66 , what are the lengths of the triangle's sides?

1 Answer

Explanation:

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Two corners of an isosceles triangle are at $(2, 5)$ $(2 ,5 )$ and $(4, 8)$ $(4 ,8 )$ . If the triangle's area is $6$ $6$ , what are the lengths of the triangle's sides?