Two corners of an isosceles triangle are at $(2, 6)$ $(2 ,6 )$ and $(3, 8)$ $(3 ,8 )$ . If the triangle's area is $48$ $48$ , what are the lengths of the triangle's sides?

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Two corners of an isosceles triangle are at $(2, 6)$ $(2 ,6 )$ and $(3, 8)$ $(3 ,8 )$ . If the triangle's area is $48$ $48$ , what are the lengths of the triangle's sides?

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Answer 1 · 2017-12-11T08:25:33

Measure of the three sides are (2.2361, 49.1212, 49.1212)

Explanation:

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Length $a = \sqrt{{(3 - 2)}^{2} + {(8 - 6)}^{2}} = \sqrt{5} = 2.2361$ $a = sqrt((3-2)^2 + (8-6)^2) = sqrt 5 = 2.2361$

Area of $Delta = 64$
$:. h = (Area) / (a/2) = 48 / (2.2361/2) = 64 / 1. 1181= 43.9327$
$side b = sqrt((a/2)^2 + h^2) = sqrt((1.1181)^2 + (43.9327)^2)$
$b = 49.1212$

Since the triangle is isosceles, third side is also $= b = 49.1212$

Measure of the three sides are (2.2361, 49.1212, 49.1212)

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Two corners of an isosceles triangle are at $(2, 6)$ $(2 ,6 )$ and $(3, 8)$ $(3 ,8 )$ . If the triangle's area is $48$ $48$ , what are the lengths of the triangle's sides?

1 Answer

Explanation:

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Two corners of an isosceles triangle are at (2 ,6 )(2,6)(2 ,6 ) and (3 ,8 )(3,8)(3 ,8 ). If the triangle's area is 48 4848 , what are the lengths of the triangle's sides?

1 Answer

Explanation:

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Two corners of an isosceles triangle are at $(2, 6)$ $(2 ,6 )$ and $(3, 8)$ $(3 ,8 )$ . If the triangle's area is $48$ $48$ , what are the lengths of the triangle's sides?