Two corners of an isosceles triangle are at $(4 ,2 )$ and $(5 ,7 )$ . If the triangle's area is $3$ , what are the lengths of the triangle's sides?

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Answer 1 · 2017-12-28T05:46:45

Measure of the three sides are 5.099, 3.4696, 3.4696

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Length of the base $a = sqrt((5-4)^2 + (7-2)^2) = 5.099$

Given area $= 3 = (1/2) * a * h$

$:. h = 6 / (5.099 /2) = 2.3534$

Length of one of the equal sides of the isosceles triangle is
$b = sqrt((a/2)^2 + h^2) = sqrt((5.099/2)^2 + (2.3534)^2) = 3.4696$

Lengths of the isosceles triangle are 5.099, 3.4696, 3.4696

Two corners of an isosceles triangle are at (4 ,2 )(4 ,2 ) and (5 ,7 )(5 ,7 ). If the triangle's area is 3 3 , what are the lengths of the triangle's sides?