Two corners of an isosceles triangle are at (5 ,2 )(5,2) and (2 ,1 )(2,1). If the triangle's area is 8 8, what are the lengths of the triangle's sides?

1 Answer
Dec 11, 2017

Measure of the three sides are (3.1623, 5.3007, 5.3007)

Explanation:

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Length a = sqrt((2-5)^2 + (1-2)^2) = sqrt 10 = 3.1623a=(25)2+(12)2=10=3.1623

Area of Delta = 8
:. h = (Area) / (a/2) = 8 / (3.1623/2) = 8 / 1.5812 = 5.0594
side b = sqrt((a/2)^2 + h^2) = sqrt((1.5812)^2 + (5.0594)^2)
b = 5.3007

Since the triangle is isosceles, third side is also = b = 5.3007

Measure of the three sides are (3.1623, 5.3007, 5.3007)