Two corners of an isosceles triangle are at (6 ,3 )(6,3) and (4 ,8 )(4,8). If the triangle's area is 8 8, what are the lengths of the triangle's sides?

1 Answer
Jan 9, 2018

Lengths of the three sides are color(blue)(5.3852, 3.8752, 3.8752)5.3852,3.8752,3.8752

Explanation:

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Given B(6,3), C(4,8), A_t = 8B(6,3),C(4,8),At=8

BC = color(red)(a ) = sqrt((4-6)^2 + (8-3)^2) = color(red)(5.3852)BC=a=(46)2+(83)2=5.3852

AD = h = (2 * A_t ) / a = (2 * 8) / 5.3852 = color(red)(2.9711)AD=h=2Ata=285.3852=2.9711

AC = AB = b = c = sqrt((a/2)^2 + h^2) = sqrt((5.3852/2)^2 + 2.7911^2)AC=AB=b=c=(a2)2+h2=(5.38522)2+2.79112

color(red)(b = 3.8782)b=3.8782

Lengths of the three sides are color(blue)(5.3852, 3.8752, 3.8752)5.3852,3.8752,3.8752