Two corners of an isosceles triangle are at $(8, 2)$ $(8 ,2 )$ and $(4, 7)$ $(4 ,7 )$ . If the triangle's area is $9$ $9$ , what are the lengths of the triangle's sides?

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Two corners of an isosceles triangle are at $(8, 2)$ $(8 ,2 )$ and $(4, 7)$ $(4 ,7 )$ . If the triangle's area is $9$ $9$ , what are the lengths of the triangle's sides?

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Answer 1 · 2017-12-11T08:48:51

Measure of the three angles are (2.8111, 4.2606, 4.2606)

Explanation:

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Length $a = \sqrt{{(8 - 4)}^{2} + {(2 - 7)}^{2}} = \sqrt{41} = 6.4031$ $a = sqrt((8-4)^2 + (2-7)^2) = sqrt 41 = 6.4031$

Area of $Delta = 64$
$:. h = (Area) / (a/2) = 9 / (6.4031/2) = 9 / 3.2016 = 2.8111$
$side b = sqrt((a/2)^2 + h^2) = sqrt((3.2016)^2 + (2.8111)^2)$
$b = 4.2606$

Since the triangle is isosceles, third side is also $= b = 4.2606$

Measure of the three sides are (2.8111, 4.2606, 4.2606)

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Two corners of an isosceles triangle are at $(8, 2)$ $(8 ,2 )$ and $(4, 7)$ $(4 ,7 )$ . If the triangle's area is $9$ $9$ , what are the lengths of the triangle's sides?

1 Answer

Explanation:

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Two corners of an isosceles triangle are at (8 ,2 )(8,2)(8 ,2 ) and (4 ,7 )(4,7)(4 ,7 ). If the triangle's area is 9 99 , what are the lengths of the triangle's sides?

1 Answer

Explanation:

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Two corners of an isosceles triangle are at $(8, 2)$ $(8 ,2 )$ and $(4, 7)$ $(4 ,7 )$ . If the triangle's area is $9$ $9$ , what are the lengths of the triangle's sides?