Two corners of an isosceles triangle are at (8 ,5 ) and (9 ,1 ). If the triangle's area is 12 , what are the lengths of the triangle's sides?

1 Answer
Jul 23, 2018

color(maroon)("Lengths of the triangle "a = sqrt 17, b = sqrt(2593 / 68), c = sqrt(2593 / 68)

Explanation:

![https://study.com/academy/lesson/http://what-is-an-isosceles-triangle-definition-properties-theorem.html](https://useruploads.socratic.org/XySDJrnQXi74AH1iJi5s_isosceles.png)

color(red)( B(8,5), C(9,1), A_t = 12

let bar(AD) = h

bar(BC) = a = sqrt((9-8)^2 + (1-5)^2) = sqrt17

Area of triangle " A_t = 12 = (1/2) a *h = (sqrt17 h)/2

h = 24 / sqrt17

bar(AC) = bar(AB) = b = sqrt((a/2)^2 + h^2)

b = sqrt((sqrt17/2)^2 + (24/sqrt17)^2)

b = sqrt(17/4 + 576/17) = sqrt(2593/68)