Two corners of an isosceles triangle are at (8 ,6 )(8,6) and (7 ,5 )(7,5). If the triangle's area is 64 64, what are the lengths of the triangle's sides?

1 Answer
Dec 8, 2017

Measure of the three sides are (1.414, 90.5261, 90.5261)

Explanation:

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Length a = sqrt((8-7)^2 + (6-5)^2) = sqrt 2 = 1.414a=(87)2+(65)2=2=1.414

Area of Delta = 64
:. h = (Area) / (a/2) = 64 / (1.414/2) = 64 / 0.707 = 90.5233
side b = sqrt((a/2)^2 + h^2) = sqrt((0.707)^2 + (90.5233)^2)
b = 90.5261

Since the triangle is isosceles, third side is also = b = 90.5261

Measure of the three sides are (1.414, 90.5261, 90.5261)