Two electrons are 1m apart , show that the force beyween them is 2.304 x 10^(-3) ?

1 Answer

#2.304\times10^{-28}\ N#

Explanation:

Force of repulsion (F) between two electrons (each having charge #e=1.6\times10^{-19}\ C#) separated by a distance #r=1\ m# is given as

#F=\frac{1}{4\pi \epsilon_o}\frac{q_1q_2}{r^2}#

#F=9\times10^{9}\cdot \frac{1.6\times10^{-19}\cdot 1.6\times10^{-19}}{1^2}#

#=23.04\times 10^{-29}#

#=2.304\times10^{-28}\ N#