Two numbers total 36 and have a difference of 12. How do you find the two number?

Question

4132 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-06T23:30:33

The two numbers which solve this problem are $12$ $12$ and $24$ $24$

We can write two different equations from the information provided and then use substitution to solve for the two numbers.

First, lets call the numbers we are looking for $m$ $m$ and $n$ $n$ .

We now can write:

$m + n = 36$ $m + n = 36$ and $m - n = 12$ $m - n = 12$

First, solve the first equation for $m$ $m$ :

$m + n - n = 36 - n$ $m + n - n = 36 - n$

$m + 0 = 36 - n$ $m + 0 = 36 - n$

$m = 36 - n$ $m = 36 - n$

Next, we substitute $36 - n$ $36 - n$ into the second equation for $m$ $m$ and solve for $n$ $n$ :

$36 - n - n = 12$ $36 - n - n = 12$

$36 - 2 n = 12$ $36 - 2n = 12$

$36 - 2 n + 2 n - 12 = 12 + 2 n - 12$ $36 - 2n + 2n - 12 = 12 + 2n - 12$

$36 - 0 - 12 = 0 + 2 n$ $36 - 0 - 12 = 0 + 2n$

$24 = 2 n$ $24 = 2n$

$\frac{24}{2} = \frac{2 n}{2}$ $24/2 = (2n)/2$

$12 = (cancel(2)n)/cancel(2)$

$12 = n$

Finally, we can substitute $12$ for $n$ in the solution to the first equation and calculate $m$ :

$m = 36 - 12$

$m = 24$