Two objects have masses of 35 MG and 21 MG. How much does the gravitational potential energy between the objects change if the distance between them changes from 8 m to 3 m?

1 Answer
Jul 4, 2018

The gravitational force increases 7 times when the distance between the objects decreases from 8 meters to 3 meters.

Explanation:

Use the formula for Newton's law of universal gravitation:

F_"grav"=(G*m_1*m_2)/d^2,

where G is the universal gravitation constant, m_1 is the mass of the first object in kg, m_2 is the mass of the second object in kg, and d is the distance between them in meters.

Known

G=(6.67xx10^(-11) "N"*"m"^2)/(kg^2")

m_1=35color(red)cancel(color(black)("mg"))xx(1color(red)cancel(color(black)("g")))/(1000color(red)cancel(color(black)("mg")))xx(1"kg")/(1000color(red)cancel(color(black)("g")))=3.5xx10^(-5) "kg"

m_2=21color(red)cancel(color(black)("mg"))xx(1color(red)cancel(color(black)("g")))/(1000color(red)cancel(color(black)("mg")))xx(1"kg")/(1000color(red)cancel(color(black)("g")))=2.1xx10^(-5) "kg"

d_1="8 m"

d_2="3 m"

Unknown

Gravitational force, F_"grav"

Distance of 8 meters

F_"grav"=(6.67xx10^(-11) ("N"*"m"^2)/"kg"^2xx3.5xx10^(-5)"kg"*2.1xx10^(-5)"kg")/(8"m"^2")

Multiply the masses and square the distance.

F_"grav"=(6.67xx10^(-11) ("N"*color(red)cancel(color(black)("m"^2)))/color(red)cancel(color(black)("kg"))^2xx7.35xx10^(-10)color(red)cancel(color(black)("kg"^2)))/(64color(red)cancel(color(black)("m"^2)))=7.7xx10^(-22) "N"

Distance of 3 meters

F_"grav"=(6.67xx10^(-11) ("N"*"m"^2)/"kg"^2xx3.5xx10^(-5)"kg"*2.1xx10^(-5)"kg")/(3"m"^2")

Multiply the masses and square the distance.

F_"grav"=(6.67xx10^(-11) ("N"*color(red)cancel(color(black)("m"^2)))/color(red)cancel(color(black)("kg"))^2xx7.35xx10^(-10)color(red)cancel(color(black)("kg"^2)))/(9color(red)cancel(color(black)("m"^2)))=5.4xx10^(-21) "N"

Divide the force at 3 meters distance by the force at 8 meters distance.

(5.4xx10^(-21)color(red)cancel(color(black)("N")))/(7.7xx10^(-22)color(red)cancel(color(black)("N")))=7.0

The gravitational force increases 7 times when the distance between the objects decreases from 8 meters to 3 meters.