Two objects have masses of $4 MG$ and $26 MG$ . How much does the gravitational potential energy between the objects change if the distance between them changes from $7 m$ to $9 m$ ?

Question

1518 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-06T09:18:09

The change in gravitational potential energy is $=-22.02*10^-5J$

Gravitational potential is the potential energy per kilogram at a point in a field.

So the units are $J, "Joules"$

$Phi=-G(M_1M_2)/R$

The gravitational universal constant is

$G=6.67*10^-11Nm^2kg^-2$

The masses causing the field is $=M_1 kg$ and $=M_2 kg$

The mass is $M_1=4MG=4*10^6g=4*10^3kg$

The mass is $M_2=26MG=26*10^6g=26*10^3kg$

The distance between the centers is $=Rm$

The distance $R_1=7m$

The distance $R_2=9m$

Therefore,

$Phi_1=(-G*(4*10^3*26*10^3)/7)$

$Phi_2=(-G*(4*10^3*26*10^3)/9)$

So,

$Phi_1-Phi_2=(-G*(4*10^3*26*10^3)/7)-(-G*(4*10^3*26*10^3)/9)$

$=4*26*10^6*6.67*10^-11(1/9-1/7)$

$=-22.02*10^-5J$

Two objects have masses of 4 MG4 MG and 26 MG26 MG. How much does the gravitational potential energy between the objects change if the distance between them changes from 7 m7 m to 9 m9 m?