Two objects have masses of 5 MG and 8 MG. How much does the gravitational potential energy between the objects change if the distance between them changes from 140 m to 160 m?

1 Answer
Oct 9, 2017

Change in Gravitational potential energy is 3.4541\times 10^(-24) J

Explanation:

Gravitational potential energy is given by,

U=−(Gm1m2)/r

Given that,
m1=5mg=5×10^-6 kg

m2=8mg=8×10^-6 kg

Initial distance between the objects = r1=140m

Final distance between the objects = r2= 160 m

We will calculate the change in gravitational potential energy as:

When
r1= 140m m

U1 = −(Gm1m2)/(r1)

And

When r2 = 160m'

U2 =−(Gm1m2)/(r2)

Change in Gravitational Potential Energy = U2 -U1

= (−(Gm1m2)/(r2) )- (−(Gm1m2)/(r1))

= (−(Gm1m2)/(160) )- (−(Gm1m2)/(140))

= (−(7Gm1m2)/(1120) +(8Gm1m2)/(1120))

=(Gm1m2)/(1120)

Substitute the values of G, m1 and m2:

U2- U1 = (6.67\times 10^(-11) \times 5×10^-6 \times 8×10^-6)/1120

U2- U1 = (386.86\times 10^(-11) \times10^-6 \times 10^-6)/1120 J

U2- U1 = (0.34541\times 10^(-11) \times 10^-6 \times 10^-6) J

U2- U1 = (0.34541\times 10^(-23) J

U2- U1 = 3.4541\times 10^(-24) J

So, Change in Gravitational potential energy is 3.4541\times 10^(-24) J