Urgent! There is a ferris wheel of radius 30 feet. When the compartments are at their lowest, it is 2 feet off the ground. The ferris wheel makes a full revolution in 20 seconds. Using a cosine function, write an equation modelling the height of time?

Help!
Radius - 30 feet
Lowest point - 2 feet
Time for 1 revolution - 20 seconds
Write cosine function!

1 Answer
Dec 3, 2016

#h = -30cos(pi/10t) + 32#, #{t|t ≥ 0, t in RR}#

Explanation:

An equation in cosine is generally of the form #y= acos(b(x - c)) + d#, where the parameters represent the following:

#|a|#: the amplitude. When it is negative, it denotes a reflection in the x axis.

#(2pi)/b# is the period, in this case the length of time it takes for the ferris wheel to come back to its starting point.

#c# is the phase shift, or the horizontal displacement.

#d# is the vertical shift

In this case, we can instantly deduce that the period is #20# seconds. We will therefore solve for #b#.

#(2pi)/b = 20#

#2pi = 20b#

#b = (2pi)/20#

#b = pi/10#

The amplitude will be given by the formula #("max" - "min")/2#. We know the minimum height is 2 feet. Since the radius is 30 feet, the diameter measures #60# feet, and so the highest point is at #62# feet.

The amplitude is therefore #(62 - 2)/2 = 60/2 = 30#.

The vertical transformation is given by #min + amp#, or #max- amp#, which is #2 + 30 = 32#.

Finally, due to the nature of the cosine function, the cosine function always starts at a maximum (except when parameter #a# is negative, in which case it starts at a minimum). I assume that when the time starts, the people are just getting on, so the ferris wheel will be at a minimum. Therefore, #a!=30# but instead #a!=-30#.

Therefore, the equation is #h = -30cos(pi/10t) + 32#, where #h# is the height in feet and #t# is the time in seconds. We finally note the restrictions to be #{t|t ≥ 0, t in RR}#, because it is impossible to have a negative period of time. The #h# value will always be positive, so we don't have to restrict that.

Hopefully this helps!