Use divergent test to determine convergence of the following series?

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$sum_(n=0)^oo (pi/e)^n$

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Answer 1 · 2018-03-24T16:08:32

Divergent.

This is like a basic geometric series: if $|r| > 1$ , then it's divergent, and if $|r| < 1$ , then it's convergent.

Since $pi > e$ , $r > 1$ , therefore the series is divergent.

Hopefully this helps!