Using synthetic division, what is the quotient and the remainder for polynomial $P(x) = x^3 - 2x^2 - 5x +6$ divided by $(x-1)$ ?

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Answer 1 · 2017-11-20T11:09:34

$(x^2-x-6)$

we need $x^3$ so we add $x^2$

$=>$
$(x-1)(x^2$
$=>x^3-x^2$
we need $-2x^2$ so we add $-x$

$=>$
$(x-1)(x^2-x$
$=>x^3-x^2-x^2+x$
we need $-5x$ so we add $-6$

$=>$
$(x-1)(x^2-x-6$
$x^3-x^2-x^2+x-6x+6$

we have what we need so we can close it

$=>$
$(x-1)(x^2-x-6)$
$x^3-2x^2+5x+6$

$=>$
$(x^3-2x^2+5x+6)/(x-1)=(x^2-x-6)$

Using synthetic division, what is the quotient and the remainder for polynomial P(x) = x^3 - 2x^2 - 5x +6P(x) = x^3 - 2x^2 - 5x +6 divided by (x-1)(x-1)?