Water can be formed from the stoichiometric reaction of hydrogen with oxygen: $2 H_{2} (g) + O_{2} (g) + 2 H_{2} O (g)$ $2H_2(g) + O_2(g) + 2H_2O(g)$ . A complete reaction of 5.0 g of $O_{2}$ $O_2$ with excess hydrogen produces how many grams of $H_{2} O$ $H_2O$ ?

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Water can be formed from the stoichiometric reaction of hydrogen with oxygen: $2 H_{2} (g) + O_{2} (g) + 2 H_{2} O (g)$ $2H_2(g) + O_2(g) + 2H_2O(g)$ . A complete reaction of 5.0 g of $O_{2}$ $O_2$ with excess hydrogen produces how many grams of $H_{2} O$ $H_2O$ ?

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Answer 1 · 2017-01-16T16:55:05

Your equation specifies that $32 \cdot g$ $32*g$ of dioxygen and $4 \cdot g$ $4*g$ of dihydrogen give $36 \cdot g$ $36*g$ of water upon reaction, so..........

Explanation:

$2 H_{2} (g) + O_{2} (g) \to 2 H_{2} O (g)$ $2H_2(g) + O_2(g) rarr 2H_2O(g)$

We started with $\frac{5.0 \cdot g}{32.00 \cdot g \cdot m o l^{- 1}} = 0.156 \cdot m o l dioxygen$ $(5.0*g)/(32.00*g*mol^-1)=0.156*mol" dioxygen"$ .

Given excess dihydrogen, this molar quantity thus gives $2 \times 0.156 \cdot m o l$ $2xx0.156*mol$ water.

And thus, $2 \times 0.156 \cdot m o l \times 18.01 \cdot g \cdot m o l^{- 1} ≅ 6 \cdot g$ $2xx0.156*molxx18.01*g*mol^-1~=6*g$ water are evolved. Is this reaction exothermic or endothermic?

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Water can be formed from the stoichiometric reaction of hydrogen with oxygen: $2 H_{2} (g) + O_{2} (g) + 2 H_{2} O (g)$ $2H_2(g) + O_2(g) + 2H_2O(g)$ . A complete reaction of 5.0 g of $O_{2}$ $O_2$ with excess hydrogen produces how many grams of $H_{2} O$ $H_2O$ ?

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Explanation:

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Water can be formed from the stoichiometric reaction of hydrogen with oxygen: 2H_2(g) + O_2(g) + 2H_2O(g)2H2(g)+O2(g)+2H2O(g)2H_2(g) + O_2(g) + 2H_2O(g). A complete reaction of 5.0 g of O_2O2O_2 with excess hydrogen produces how many grams of H_2OH2OH_2O?

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Water can be formed from the stoichiometric reaction of hydrogen with oxygen: $2 H_{2} (g) + O_{2} (g) + 2 H_{2} O (g)$ $2H_2(g) + O_2(g) + 2H_2O(g)$ . A complete reaction of 5.0 g of $O_{2}$ $O_2$ with excess hydrogen produces how many grams of $H_{2} O$ $H_2O$ ?