What are the antiderivatives of #sin(x)# and #cos(x)#?

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Answer 1 · 2014-10-16T17:05:02

Since

#(sinx)'=cosx#,

we have

#int cosx dx=sinx +C#.

Since

#(-cosx)'=sinx#,

we have

#int sinx dx=-cosx+C#.

I hope that this was helpful.