What are the asymptotes for $\frac{4 x}{x - 3}$ $(4x)/(x-3)$ ?

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Answer 1 · 2015-07-07T03:50:11

x+3 and y=4

It has a vertical asymptote, x=3. Now divide 4x by x-3 to have y= 4 + $\frac{12}{x - 3}$ $12/(x-3)$ . This gives a horizontal asymptote, y=4

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