What are the asymptotes for f(x)=x/(x-7)f(x)=xx7?

1 Answer
Sep 21, 2015

The vertical assymptote is x = 7x=7 and the horizontal assymptote is y = 1y=1

Explanation:

Vertical assymptotes are the lines of the type x = ax=a that the function can never take because doing so will create a math error.

In this function the only possible math error is a division by zero, so we have that:
x - 7 != 0x70
x != 7x7

So 77 is a vertical assymptote. That means that as the function gets closer and closer to 7, the values of the function as whole will become bigger in magnitude (because x - 7x7 gets closer and closer to 0) but the function will never actually evaluate at that point.

Horizontal assymptotes are the lines of the type y = by=b that are basically the value the function start to take whenever xx becomes bigger and bigger. Slant assymptotes (of the type y = ax+by=ax+b) are very similar but the function isn't tending to a constant value. We can discover them the same way:

Start plugging bigger and bigger values until you see a pattern, or, use a made-up number, like, let's say bb, that is infinitely big, plug it in and see what happens.

y = b/(b-7)y=bb7

Since bb is an infinitely large number, we can say that b - 7 ~= bb7b, after all think of it like if b was a number like a billion or a trillion. A trillion minus 7 is still pretty much a trillion for practical purposes. So we have

y ~= b/bybb or y ~= 1y1

So the horizontal assymptote is y = 1y=1, that is, as xx grows bigger the function gets closer and closer to 11.

We can doublecheck it by looking at the graph:
graph{x/(x-7) [-14, 14, -28, 28]}