What are the asymptotes for $y = \frac{1}{x + 3}$ $y=1/(x+3)$ ?

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Answer 1 · 2015-09-10T22:34:43

The asymptotes are $y = 0, x = - 3$ $y=0,x=-3$

As $x \to \pm \infty$ $x->+-oo$ , $y \to 0$ $y->0$ hence $y = 0$ $y=0$ asymptote.

As $x \to - 3$ $x->-3$ , $y \to \pm \infty$ $y->+-oo$ so $x = - 3$ $x=-3$ asymptote

What are the asymptotes for y=1/(x+3)y=1x+3y=1/(x+3)?