What are the asymptotes of (x^2+4)/(6x-5x^2)?

1 Answer
Jul 14, 2018

Vertical asymptotes are x=0,x=6/5 and the horizontal asymptote is y=-1/5

Explanation:

writing your term in the form

(x^2+4)/(x(6-5x)) so we get the Asymptote when the denominator is equal to Zero:

This is x=0 or x=6/5
no we compute the Limit for x tends to infty

writing

(x^2(1+4/x^2))/(x^2(6/x-5)) and this tends to -1/5 for x tends to infinity.