What are the concentrations (ω) of carbon, hydrogen and chlorine in chlorineciklohexane?

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Answer 1 · 2016-10-28T09:45:49

Considering the compound monochlorocyclohexane $C_{6} H_{11} C l$ $C_6H_11Cl$

$C \to 12 g/mol$ $C->12" g/mol"$

$C l \to 35.5 g/mol$ $Cl->35.5" g/mol"$

$H \to 1 g/mol$ $H->1" g/mol"$

We get the molar mass of $C_{6} H_{11} C l$ $C_6H_11Cl$

$6 \cdot 12 + 11 \cdot 1 + 35.5 = 118.5 g/mol$ $6*12+11*1+35.5=118.5" g/mol"$

The percentage composition

$C \to \frac{6 \times 12}{118.5} \times 100 % = 60.76 %$ $C->(6xx12)/118.5xx100%=60.76%$

$C l \to \frac{35.5}{118.5} \times 100 % = 29.96 %$ $Cl->35.5/118.5xx100%=29.96%$

$H \to \frac{11 \times 1}{118.5} \times 100 % = 9.28 %$ $H->(11xx1)/118.5xx100%=9.28%$