What are the intercepts for $3 x - 4 y = - 5$ $3x-4y=-5$ ?

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Answer 1 · 2014-11-13T16:54:49

$3 x - 4 y = - 5$ $3x-4y=-5$

To find the $x$ $x$ -intercept, set $y = 0$ $y=0$ .

$3 x - 4 (0) = - 5 \Rightarrow 3 x = - 5$ $3x-4(0)=-5 => 3x=-5$

by dividing by $3$ $3$ ,

$\Rightarrow x = - \frac{5}{3}$ $=> x=-5/3$

Hence, the $x$ $x$ -intercept is $- \frac{5}{3}$ $-5/3$ .

To find the $y$ $y$ -intercept, set $x = 0$ $x=0$ .

$3 (0) - 4 y = - 5 \Rightarrow - 4 y = - 5$ $3(0)-4y=-5 => -4y=-5$

by dividing by $- 4$ $-4$ ,

$\Rightarrow y = \frac{- 5}{- 4} = \frac{5}{4}$ $=> y={-5}/{-4}=5/4$

Hence, the $y$ $y$ -intercept is $\frac{5}{4}$ $5/4$ .

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