What are the intercepts of $- y = 3 y - 6 x - 9$ $-y=3y-6x-9$ ?

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Answer 1 · 2016-04-12T18:31:14

$y$ $y$ -intercept is $(0, 2.25)$ $(0,2.25)$

$x$ $x$ -intercept is $(- 1.5, 0)$ $(-1.5,0)$

The $y$ $y$ -intercept is the point where the line cuts the $y$ $y$ -axis.
This means, we have to find the point when $x = 0$ $x=0$ .

Similarly, the $x$ $x$ -intercept is the point where the line cuts the $x$ $x$ -axis. i.e. to find the point when $y = 0$ $y=0$ .

Pretty simple.

Here, first let's write the equation in terms of $y$ $y$ .

$- y = 3 y - 6 x - 9$ $-y=3y-6x-9$

$\Rightarrow - 3 y - y = - 6 x - 9$ $=>-3y-y=-6x-9$

Multiply both sides by $- 1$ $-1$

$\Rightarrow 3 y + y = 6 x + 9$ $=>3y+y=6x+9$

$\Rightarrow 4 y = 6 x + 9$ $=>4y=6x+9$

$\Rightarrow y = \frac{6 x + 9}{4}$ $=>y=(6x+9)/4$

Below is a step-by-step to work out the $y$ $y$ -intercept and $x$ $x$ -intercept .

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The graph shows the line cutting the two axes.

What are the intercepts of −y=3y−6x−9-y=3y-6x-9?