Question

What are the mean and standard deviation of a binomial probability distribution with `n=88` and `p=24/32`?

Answer 1

`E(X)=66`

`sd=sqrt(22)`

Explanation:

for a Binomial distribution

`X~B(n,p)`

in this case

`X~B(88,24/32)`

or`" "X~B(88,3/4)`

mean`" "E(X)=np`

in this case

`E(X)=88xx3/4=66`

standard deviation =`sqrt"variance"`

`sd=sqrt(np(1-p))`

`sd=sqrt(66xx1/4)`

`sd=sqrt22`