What are the products of lead (II) acetate + hydrogen sulfide →?

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Answer 1 · 2017-02-01T08:07:38

$Lead sulfide.........and acetic acid$ $"Lead sulfide.........and acetic acid"$

This is a simple acid/base reaction...........

All sulfides are insoluble; lead sulfide is particularly insoluble.

$P b^{2 +} + S^{2 -} \to P b S (s) ⏐ ↓$ $Pb^(2+) + S^(2-) rarr PbS(s)darr$

This is the net ionic equation.

The stoichiometric equation would be:

$P b {(O A c)}_{2} (a q) + H_{2} S (a q) \to P b S (s) ⏐ ↓ + 2 H O A c (a q)$ $Pb(OAc)_2(aq) + H_2S(aq) rarr PbS(s)darr + 2HOAc(aq)$

$H O A c = H O (O =) C - C H_{3}$ $HOAc=HO(O=)C-CH_3$

A black precipitate of lead sulfide would precipitate with alacrity.