What are the structures of the isomers of dichloropropane?

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Answer 1 · 2015-11-11T23:26:08

See below.

Start with a $"Cl"$ at one end and then put a second $"Cl"$ in every possible position.

This gives us

1. $"CH"_3"CH"_2"CHCl"_2$ , 1,1-dichloropropane

and

2. $"CH"_3"CHClCH"_2"Cl"$ , 1,2-dichloropropane

and

3. $"ClCH"_2"CH"_2"CH"_2"Cl"$ , 1,3-dichloropropane

Now put a $"Cl"$ on the middle carbon and put the second $"Cl"$ in all possible locations.

This gives only one more isomer

$"CH"_3"CCl"_2"CH"_3$ , 2,2-dichloropropane

And there you have the four isomers of dichloropropane.