What are the values and types of the critical points, if any, of #f(x)=cos^2 x - sin^2 x #?
1 Answer
Apr 11, 2018
We can rewrite as
#f(x) = cos(2x)#
Which has first derivative
#f'(x) = -2sin(2x)#
This has critical points at
The graph demonstrates:
graph{(cosx + sinx)(cosx - sinx) [-16.02, 16.02, -8.01, 8.01]}
Hopefully this helps!